How to calculate this stereo sound ?Please help.

[siauhong]

The 44.1KHz sampling frequency and 16-bit digital code of stereo CD audio result in the need to process and record about 150,000 bits of data every second, about 9MB per minute.

How to obtain the answer 150,000 bits with sampling rate 44.1 KHZ and sample size 16-bit ?
*(remeber stereo 2 channels)

[alsyed]

44.1 KHZ = 44100 HZ = 44100 cycles per second
16 bit X 2 = 32 bits = 4 bytes per each cycle

44100 x 4 = 176400 bytes per second

176400 bytes = 172.26 Kbytes per scond

x 60 = 10335.9 Kbytes per minute
= 10.09 MB per minute

150,000 doesn't come into it

[Cornucopia]

Maybe he/she is thinking:
176,400 bytes * 8 bits/byte = 1,411,200 bits ?

I dunno.

Only other thing that comes to mind is CDROM 1x read rates:

CDDA rate:
172.26kBps / 75 Frames (Logical Blocks)perSecond = 2352 Bytes/block

but because of overhead, CDROM has:

2048 Bytes/block

2048 * 75 = 153,600 kBytes/second


Scott