Creating variables for ffprobe output in Windows and Linux

[wiseant]

Hi

In Windows I am using this bat file - I either drag and drop a file on it or select a file and use sendto

c:\ffmpeg\bin\ffprobe -v quiet -of default=noprint_wrappers=0 -print_format flat -select_streams a:0 -show_entries stream=codec_name -i "%~dpnx1"

c:\ffmpeg\bin\ffprobe -v quiet -of default=noprint_wrappers=0 -print_format flat -select_streams v:0 -show_entries stream=codec_name -i "%~dpnx1"

pause

this is the output:

E:\>c:\ffmpeg\bin\ffprobe -v quiet -of default=noprint_wrappers=0 -print_format flat -select_streams a:0 -show_entries stream=codec_name -i "E:\Palookaville.mp4"
streams.stream.0.codec_name="aac"

E:\>c:\ffmpeg\bin\ffprobe -v quiet -of default=noprint_wrappers=0 -print_format flat -select_streams v:0 -show_entries stream=codec_name -i "E:\Palookaville.mp4"
streams.stream.0.codec_name="h264"

E:\>pause
Press any key to continue . . .

How do I create variable for streams.stream.0.codec_name="aac" and streams.stream.0.codec_name="h264"

Ideally I want variables for the audio codec name, in this case "aac" and for the video codec name, in this case "h264"


What I want to do is create a bat file that does the same thing as this Linux script - ffprobe.sh

#!/bin/bash
INFO=$(ffprobe -i "$1" -v quiet -of default=noprint_wrappers=0 -print_format flat -select_streams a:0 -show_entries stream=codec_name)
echo $INFO
b=${INFO:28}
if [[ "$b" == '"opus"' ]]; then codeca="ogg"; fi
if [[ "$b" == '"ac3"' ]]; then codeca="ac3"; fi
if [[ "$b" == '"aac"' ]]; then codeca="m4a"; fi
if [[ "$b" == '"mp3"' ]]; then codeca="mp3"; fi
echo demuxed audio file: "${1%.*}.$codeca"
INFO1=$(ffprobe -i "$1" -v quiet -of default=noprint_wrappers=0 -print_format flat -select_streams v:0 -show_entries stream=codec_name)
echo $INFO1
c=${INFO1:28}
if [[ "$c" == '"h264"' ]]; then codecv="m4v"; fi
if [[ "$c" == '"vp9"' ]]; then codecv="mkv"; fi
echo demuxed video file: "${1%.*}.$codecv"
ffmpeg -i "$1" -v quiet -vn -acodec copy "${1%.*}.$codeca"
ffmpeg -i "$1" -v quiet -an -vcodec copy "${1%.*}.$codecv"
$SHELL

In Linux, for the file[s] I want to process I use sendto [in the /usr/share/Thunar/sendto directory I have ffprobe.desktop ]

this is the output:
streams.stream.0.codec_name="aac"
demuxed audio file: /media/unoit/Backup/Palookaville.m4a
streams.stream.0.codec_name="h264"
demuxed video file: /media/unoit/Backup/Palookaville.m4v

TIA

[_Al_]

here is an example:
https://forum.videohelp.com/threads/412365-How-to-calculate-the-average-bitrate-of-video#post2712856

it can be done without creating temp files (if it is important) , check example below in the same thread:
https://forum.videohelp.com/threads/412365-How-to-calculate-the-average-bitrate-of-video#post2713099

[wiseant]

@_Al_

Thanks for the heads up

This is my preliminary batch file - ffprobe.bat

ECHO OFF
SETLOCAL ENABLEDELAYEDEXPANSION
set "arg[0]=codec_name"
C:\ffmpeg\bin\ffprobe.exe -v quiet -select_streams v:0 -show_entries stream=%arg[0]% -of default=noprint_wrappers=1:nokey=1 -i "%~dpnx1" >video.txt
C:\ffmpeg\bin\ffprobe.exe -v quiet -select_streams a:0 -show_entries stream=%arg[0]% -of default=noprint_wrappers=1:nokey=1 -i "%~dpnx1" >audio.txt
set /p codecv=<video.txt
set /p codeca=<audio.txt
if %codeca% == aac set myaudio=m4a
if %codeca% == ac3 set myaudio=ac3
if %codecv% == h264 set myvideo=m4v
if %codecv% == vp9 set myvideo=mkv
echo original file is "%~dpnx1"
echo demuxed audio is "%~dpn1.%myaudio%"
echo demuxed video is "%~dpn1.%myvideo%"
c:\ffmpeg\bin\ffmpeg -v quiet -i "%~dpnx1" -vn -c:a copy "%~dpn1.%myaudio%"
c:\ffmpeg\bin\ffmpeg -v quiet -i "%~dpnx1" -an -c:v copy "%~dpn1.%myvideo%"
pause


and the output is

E:\>ECHO OFF
original file is "E:\Palookaville.mp4"
demuxed audio is "E:\Palookaville.m4a"
demuxed video is "E:\Palookaville.m4v"
Press any key to continue . . .