MiniDV -- miniDVD bitrate question

[Stoxx]

As far as I know, miniDV has a 3.5Mb/s datarate (approx. 12Gb/hour). When I encode this original video in TMPGEnc using the DVD template, the suggested datarate is 8,000kb/s (8.0Mb/s). Logic says that it doesn't make sense that the result of encoding is bigger than the original. Unless I get my bits and bytes confused again or just plain not understand this.

Can somebody confirm or explain this and give a recommendation on the datarate to use (miniDV --> miniDVD). How many minutes of video would still give DVD-like results on a 80 min. CD-R?

Thanks,

Stoxx

[Stoxx]

Anybody?

[ktnwin]

Nop, miniDVD is simply "DVD ready" MPEG-2 burned on a CD-R. So the bit rate should be the one of the DVD (6000 to 9000 Kbps).

Your statement "miniDV has a 3.5Mb/s datarate(approx 12Gb/hour)" is not true. That's the data rate for a DV tape.
This should be equivalent to 3.5x8 = 28,000 Kbps. That's why it is sooooo gooood.

If your DVD player can play miniDVD format, then the play time would be (with calculation, assuming 700MB disc)

at 1150 kbps, you get 80min
at 6000 kpbs, you get 80 x 1150 / 6000 = 15 min.

(I found that the resolution of the MPEG-1 or MPEG-2 file does not seem to affect the resulting file size, only the bit rate does)

Or another way, a DVD with 4.7GB (4700 MB) can hold 2 hours.
So 700MB can hold: 120 x 700 / 4700 = 17min roughly
This is just a rough estimate which does not account for other things beside just the MPEG file.

You should get the idea by now.