View Profile
View Forum Posts
If an army forty miles long advances forty miles while a dispatch rider gallops from the rear to the front, delivers a dispatch to the commanding general, and returns to the rear, how far has he to travel?
P.S. The answer is not 80 miles.
If anyone can get this let me know becuase I can't.
+ Reply to Thread
Results 1 to 5 of 5
-
-
well the key to this is that the army is moving...
so the guy gallops up and then he gallops back... remember they are moving...
so like 40miles or something?! -
Free Flying Soul
- Feb 2002
- United States
i would guess 120 miles, since it will take 80 miles just for the rider to get to the front of the army, then he has to travel the 40 mile distance back to the end. This question really seems flawed because i would think the speed of the marching army and the speed of the rider would apply also.
-
i also guessed 80miles to get in front.
he goes 20 towards the end and they come 20 towards him=40
so i say 100 -
ok,he is going twice as fast.
he goes 26.66 towards the end
they go 13.33 towards him which =39.99 (40
)
so 80+26.66=106.66
my brain hurts now
Quote
Visit Homepage