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  1. 3rd Sep 2001 18:35 #1
    vivisimonvi
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    Here's something I hope someone can figure out. There's a formula for setting the bitrate equal to say 800 Megabytes. This equation isn't correct but just an example:

    [audio + video bitrate in kbps] X [seconds] X [minutes] = [megabytes]

    I'm trying to maximize to amount of video data I can put on a disc as XVCD that's less than 80 minutes.
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  2. 3rd Sep 2001 19:01 #2
    KuskenLars
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    ((Audio+Video bitrate in kbps)/*60*time in mins = size

    Audio+Video bitrate in kbps = (size/time in mins) * 133.3333333333 (that means 133 + 1/3)

    hope it works
    remember to use correct audio br (128,128,192,224)


    Magnus Jensen

    A.K.A Geezus
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  3. 3rd Sep 2001 19:02 #3
    KuskenLars
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    not /8 but divided by 8...
    Magnus Jensen

    A.K.A Geezus
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