I need help decrypting the following code:
I am looking for a PHP code that can decrypt similar codes like this one. The result of this code is:Code:Bg4VB0MdWlwWExcNERUPQhYOD1cvKD44LWRaXRcQFxRXGVUZVkgBFwUfD0pKCkEBGEFDDkpBUw5cQRBMCB5QFRoAEwcdRUpUS0VXDkNaHR0PHgQFCg8ARxwGXw0eEQgYUwJHSF4
Is there any expert who knows the decryption key?Code:http://hogeahai.xyz/AR_OTV/index.m3u8?token=3845a51b355b26e4fd1bc2f3d188211b
The encrypted code and the link were obtained from the elAhmad app.
Code:https://www.mediafire.com/file/axc9zt6sgt77ldl/Elahmad_v3.0.apk/file
[Attachment 82600 - Click to enlarge]
[Attachment 82601 - Click to enlarge]
[Attachment 82602 - Click to enlarge]
[Attachment 82603 - Click to enlarge]
[Attachment 82604 - Click to enlarge]
Thank you!
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Last edited by brossmee; 2nd Oct 2024 at 10:53.
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You have to give us the page url so we can take a look at the source code. We can't guess how this url was encoded/encrypted without more information..
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Hi,
You can extract the encrypted code from the app by following the steps shown in the screenshots to access the specific channel. -
For the website:
Code:from Crypto.Cipher import AES from Crypto.Util.Padding import unpad import base64 def my_crypt( data: str, key: bytes, iv: bytes ) -> str: encrypted_data = base64.b64decode(data) cipher = AES.new( key=key, mode=AES.MODE_CBC, iv=iv ) decrypted_data = unpad( padded_data=cipher.decrypt(encrypted_data), block_size=AES.block_size ) return decrypted_data.decode('utf-8') if __name__ == '__main__': print(my_crypt( "wLflWLnjQtvqkFGnx4Jmc1hakJmiRdXMpSLnV5xZc3viU4zHpRC/k2WSDGrh96wmJN11yPXZgCA4CJJr1P+b1A==", '139323cde60cb1cabab94bfe1a8818d7'.encode(), 'fb2ebeb90bb35816'.encode() ))
Last edited by larley; 2nd Oct 2024 at 14:27.
Bypass HMACs, One-time-tokens and Lic.Wrapping: https://github.com/DevLARLEY/WidevineProxy2 -
Thank you, brother, but it’s not working for me; it doesn't return any results.
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Did you try it on the website?
It turns out that the AES key and IV change per video / php file. You can find the key and iv at the end of the php fileLast edited by larley; 2nd Oct 2024 at 15:56.
Bypass HMACs, One-time-tokens and Lic.Wrapping: https://github.com/DevLARLEY/WidevineProxy2 -
I tried, but it didn't work. I want to extract the stream link from this URL:
Code:https://www.elahmad.net/app_108/dh_2.php?id=840
Code:<?php // Initialize cURL session $curl = curl_init(); // Set the URL $url = "https://www.elahmad.net/app_108/dh_2.php?id=840"; // Set cURL options curl_setopt_array($curl, [ CURLOPT_URL => $url, CURLOPT_RETURNTRANSFER => true, CURLOPT_HTTP_VERSION => CURL_HTTP_VERSION_2_0, CURLOPT_HTTPHEADER => [ "Host: www.elahmad.net", "encrypted: yes", "user-agent: elahmad-tv.com", ], ]); // Execute the request $response = curl_exec($curl); // Check for errors if (curl_errno($curl)) { echo 'Error:' . curl_error($curl); } else { // Print the response echo $response; } // Close cURL session curl_close($curl); ?>
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Did you even read my message? I said that it only works for the website.
I don't have time to disassemble an android app.
Why are you even trying to get the response from the app? The website offers the same channelsBypass HMACs, One-time-tokens and Lic.Wrapping: https://github.com/DevLARLEY/WidevineProxy2 -
--[----->+<]>.++++++++++++.---.--------.
[*drm mass downloader: widefrog*]~~~[*how to make your own mass downloader: guide*] -
The website link
Code:https://www.elahmad.net/app_108/dh_2.php?id=840
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Disassemble the android app and look for implementations
Bypass HMACs, One-time-tokens and Lic.Wrapping: https://github.com/DevLARLEY/WidevineProxy2 -
Thank you for your advice. Due to my limited experience, I searched but couldn't find a solution, so I turned to this forum hoping to find someone more experienced than me.
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From website
Code:https://www.elahmad.com/tv/mobile_tv_live/
Code:https://muutube.sonmezalp.com/proxy.php/https://mysat-live.ercdn.net/otv/otv_720p.m3u8
Code:https://raw.githubusercontent.com/rrosajp/xml/c463aeb52c6993cc4afd642f91ee557f2ee9338c/foreign_channels/lb.m3u
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