Calculate computer performance increase?

[ziggy1971]

I'm trying to figure out how to calculate the increase in performance between PC configurations.

For instance:
PC X takes 0:13:15 (hour, mins, secs) to render a 5 minute video
PC Y takes 0:04:31 to render the same 5 minute video

Basically, how much faster is PC Y than PC X in this situation?

It's confusing for me because the new value is lower than the original. I tried the formula

(increased amount - original amount) / original amount x 100

but it gives me a number that doesn't look right.

I hope I can get an answer to this, I'm starting to feel really dumb

[davexnet]

A simple answer could be derived by converting the times into seconds and dividing one into the other.
13.15 is 795 seconds, 4.31 is 271 seconds.
795/271=3.44,

The faster PC is almost 3 1/2 times faster than the slower.

[ziggy1971]

I don't see how you get 3.44.

My calculator says 795/271 = approx. 2.934

[jagabo]

Yeah, I get ~2.93 too. I suspect davexnet made a typo: 795/231=3.44.

You can also look at this the other way around: 271/795 = 0.34. So the faster CPU reduced the conversion time by 66 percent.

[Bjs]

even without converting to seconds, pc Y is almost 300% faster than pc X by simply dividing the larger time by the lower time.

and its 2.9335 or 293.35%

[roma_turok]

1) Find you current CPU in CPU Benchmarks site
2) Get benchmarks value of current CPU: CPU Mark (higher is better)) and Rank(lower is better)
3) Find CPU you want to compare in CPU Benchmarks site
4) Compare 2 CPUs benchmarks values and calculate in percents increase

It not will be 100% correct but it give you some indication

[jagabo]

even without converting to seconds, pc Y is almost 300% faster than pc X by simply dividing the larger time by the lower time.

and its 2.9335 or 293.35%

That makes it 200 percent faster, not 300 percent.