I used G spot to find the bitrate on two different WMV video files. The first file is 3:41 long, is 640x480, has a bitrate of 1348 kbps for a total file size of 38.9MB.
The second file is 3:04 long, is 1280x720, has a bitrate of 6500 kbps and is 49MB. I would think the second video would be 3 times that size. How is that possible?
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Originally Posted by Landshark92
It seems 49.0/38.9 = 1.26 indicates the 720p guy requested more compression than the 480p guy.
Try encoding yourself with WME
http://www.microsoft.com/windows/windowsmedia/forpros/encoder/default.mspxRecommends: Kiva.org - Loans that change lives.
http://www.kiva.org/about -
They are actually different files altogether with different content. Isn't the filesize determined by bitrate x seconds of content? For the 6500 kbps file, it should come out to around 150MB. The file looks great and I can't believe it is only 49MB.
Ill try the mediainfo and see what it says. If there were extra audio tracks in there, the file should be even bigger than it is. I am trying to figure this out because I would love to get a high bit rate out of a small file size -
Probably you are being informed about the average or the nominal/maximum bitrate values,
NOT the actual ones (which vary along the running time of the video).
BTW, I am not aware of any bitrate-viewing application for WMV files.
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UPDATE:
AVInaptic promises to be capable of the deed.
Downloading it now, wanna see it with my own two eyes.
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Okay, this is weird. When I put my cursor over the file on my desktop, it says 6346 kbps. When I run Gspot, it says 6127 kbps. When I tried it on Mediainfo, it says 2048 kbps. For the file size, 2048 sounds just about perfect and accurate. Guess Ill need to cross check with different programs to make sure from now on. Thanks for the guidance and I guess I learn something new everyday.
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