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  1. Member rkr1958's Avatar
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    In TDA if, for example, the run time displayed for an encoded NTSC video file under the edit screen: 1:29:15;11 (where ;11 is frame 11) is the total running time 1:2915+11/29.97) > 1:29:15.3670 or is it 1:2915+12/29.97) > 1:29:15.4004? In other words do you add in frame 0 to get the fraction for seconds?

    I often use the timewarp function in Goldwave to ensure that the audio stream is the same length as the video stream. For this calcuation I've been using the former method (i.e., not including frame 0).
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  2. Always Watching guns1inger's Avatar
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    Can TDA do frame accurate editing, or is it limited to I-frames ? Frame accurate editing of mpeg source requires re-encoding of the last GOP, which implies the use on an encoder at some point in the process.
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  3. Member ZippyP.'s Avatar
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    Originally Posted by guns1inger
    Can TDA do frame accurate editing, or is it limited to I-frames ?
    No and yes, I frames edits only.
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  4. Member rkr1958's Avatar
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    Originally Posted by guns1inger
    Can TDA do frame accurate editing, or is it limited to I-frames ? Frame accurate editing of mpeg source requires re-encoding of the last GOP, which implies the use on an encoder at some point in the process.
    I-frames only. If I need to cut on anything other than I-frames I use Cuttermaran w/TMPGEnc-Plus. With this tool if you make an in-cut on a P or B-frame or an out-cut on a I or B-frame then Cuttermaran (freeware) uses the encoder you've select to reencode the affected GOPs. It also does a great job cutting and keeping the audio in sync. The only requirement is that you need to demux the audio and video before you use it. I use PVAStrumento (freeware), another wonderful tool, for this.

    I posted my original question over at doom9 and got a response the following response that I thought I'd share.

    http://forum.doom9.org/showthread.php?p=869954#post869954

    Originally Posted by Zeul
    You're frame 11 will be 11/30 -> actual play time is 30fps, encoded is 29.97 but with drop frame. So 11f = 0.366s
    The drop frame didn't occur to me. Now a follow question. In terms of considering the drop frame is the following logic correct?

    hr:minec;fn

    if sec != 0 && int(min/10)*10 != min
    sec' = sec + fn/30
    else
    sec' = sec + fn/28
    end
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